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5(4x+4)=(3x-5)3
We move all terms to the left:
5(4x+4)-((3x-5)3)=0
We multiply parentheses
20x-((3x-5)3)+20=0
We calculate terms in parentheses: -((3x-5)3), so:We get rid of parentheses
(3x-5)3
We multiply parentheses
9x-15
Back to the equation:
-(9x-15)
20x-9x+15+20=0
We add all the numbers together, and all the variables
11x+35=0
We move all terms containing x to the left, all other terms to the right
11x=-35
x=-35/11
x=-3+2/11
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