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5(4x+1)+1=2(x+3)
We move all terms to the left:
5(4x+1)+1-(2(x+3))=0
We multiply parentheses
20x-(2(x+3))+5+1=0
We calculate terms in parentheses: -(2(x+3)), so:We add all the numbers together, and all the variables
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
20x-(2x+6)+6=0
We get rid of parentheses
20x-2x-6+6=0
We add all the numbers together, and all the variables
18x=0
x=0/18
x=0
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