5(4c-2)=2(2c+19)

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Solution for 5(4c-2)=2(2c+19) equation:


Simplifying
5(4c + -2) = 2(2c + 19)

Reorder the terms:
5(-2 + 4c) = 2(2c + 19)
(-2 * 5 + 4c * 5) = 2(2c + 19)
(-10 + 20c) = 2(2c + 19)

Reorder the terms:
-10 + 20c = 2(19 + 2c)
-10 + 20c = (19 * 2 + 2c * 2)
-10 + 20c = (38 + 4c)

Solving
-10 + 20c = 38 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
-10 + 20c + -4c = 38 + 4c + -4c

Combine like terms: 20c + -4c = 16c
-10 + 16c = 38 + 4c + -4c

Combine like terms: 4c + -4c = 0
-10 + 16c = 38 + 0
-10 + 16c = 38

Add '10' to each side of the equation.
-10 + 10 + 16c = 38 + 10

Combine like terms: -10 + 10 = 0
0 + 16c = 38 + 10
16c = 38 + 10

Combine like terms: 38 + 10 = 48
16c = 48

Divide each side by '16'.
c = 3

Simplifying
c = 3

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