5(4c+9)=3(7c-1)

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Solution for 5(4c+9)=3(7c-1) equation:



5(4c+9)=3(7c-1)
We move all terms to the left:
5(4c+9)-(3(7c-1))=0
We multiply parentheses
20c-(3(7c-1))+45=0
We calculate terms in parentheses: -(3(7c-1)), so:
3(7c-1)
We multiply parentheses
21c-3
Back to the equation:
-(21c-3)
We get rid of parentheses
20c-21c+3+45=0
We add all the numbers together, and all the variables
-1c+48=0
We move all terms containing c to the left, all other terms to the right
-c=-48
c=-48/-1
c=+48

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