5(4b+3)=(5b+1)2

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Solution for 5(4b+3)=(5b+1)2 equation: 



5(4b+3)=(5b+1)2

We move all terms to the left:

5(4b+3)-((5b+1)2)=0

We multiply parentheses

20b-((5b+1)2)+15=0



We calculate terms in parentheses: -((5b+1)2), so:

(5b+1)2

We multiply parentheses

10b+2

Back to the equation:

-(10b+2)



We get rid of parentheses

20b-10b-2+15=0

We add all the numbers together, and all the variables

10b+13=0

We move all terms containing b to the left, all other terms to the right

10b=-13

b=-13/10

b=-1+3/10

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