5(4-x)=10(2-x)

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Solution for 5(4-x)=10(2-x) equation: 



5(4-x)=10(2-x)

We move all terms to the left:

5(4-x)-(10(2-x))=0

We add all the numbers together, and all the variables

5(-1x+4)-(10(-1x+2))=0

We multiply parentheses

-5x-(10(-1x+2))+20=0



We calculate terms in parentheses: -(10(-1x+2)), so:

10(-1x+2)

We multiply parentheses

-10x+20

Back to the equation:

-(-10x+20)



We get rid of parentheses

-5x+10x-20+20=0

We add all the numbers together, and all the variables

5x=0

x=0/5

x=0

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