5(4-x)+2x=6(2x-3)+14

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Solution for 5(4-x)+2x=6(2x-3)+14 equation: 



5(4-x)+2x=6(2x-3)+14

We move all terms to the left:

5(4-x)+2x-(6(2x-3)+14)=0

We add all the numbers together, and all the variables

5(-1x+4)+2x-(6(2x-3)+14)=0

We add all the numbers together, and all the variables

2x+5(-1x+4)-(6(2x-3)+14)=0

We multiply parentheses

2x-5x-(6(2x-3)+14)+20=0



We calculate terms in parentheses: -(6(2x-3)+14), so:

6(2x-3)+14

We multiply parentheses

12x-18+14

We add all the numbers together, and all the variables

12x-4

Back to the equation:

-(12x-4)



We add all the numbers together, and all the variables

-3x-(12x-4)+20=0

We get rid of parentheses

-3x-12x+4+20=0

We add all the numbers together, and all the variables

-15x+24=0

We move all terms containing x to the left, all other terms to the right

-15x=-24

x=-24/-15

x=1+3/5

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