5(4-2y)=4(2y-5)

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Solution for 5(4-2y)=4(2y-5) equation: 



5(4-2y)=4(2y-5)

We move all terms to the left:

5(4-2y)-(4(2y-5))=0

We add all the numbers together, and all the variables

5(-2y+4)-(4(2y-5))=0

We multiply parentheses

-10y-(4(2y-5))+20=0



We calculate terms in parentheses: -(4(2y-5)), so:

4(2y-5)

We multiply parentheses

8y-20

Back to the equation:

-(8y-20)



We get rid of parentheses

-10y-8y+20+20=0

We add all the numbers together, and all the variables

-18y+40=0

We move all terms containing y to the left, all other terms to the right

-18y=-40

y=-40/-18

y=2+2/9

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