5(4-2l)=7(3+l)

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Solution for 5(4-2l)=7(3+l) equation: 



5(4-2l)=7(3+l)

We move all terms to the left:

5(4-2l)-(7(3+l))=0

We add all the numbers together, and all the variables

5(-2l+4)-(7(l+3))=0

We multiply parentheses

-10l-(7(l+3))+20=0



We calculate terms in parentheses: -(7(l+3)), so:

7(l+3)

We multiply parentheses

7l+21

Back to the equation:

-(7l+21)



We get rid of parentheses

-10l-7l-21+20=0

We add all the numbers together, and all the variables

-17l-1=0

We move all terms containing l to the left, all other terms to the right

-17l=1

l=1/-17

l=-1/17

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