5(4+k)=4(3+k)

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Solution for 5(4+k)=4(3+k) equation: 



5(4+k)=4(3+k)

We move all terms to the left:

5(4+k)-(4(3+k))=0

We add all the numbers together, and all the variables

5(k+4)-(4(k+3))=0

We multiply parentheses

5k-(4(k+3))+20=0



We calculate terms in parentheses: -(4(k+3)), so:

4(k+3)

We multiply parentheses

4k+12

Back to the equation:

-(4k+12)



We get rid of parentheses

5k-4k-12+20=0

We add all the numbers together, and all the variables

k+8=0

We move all terms containing k to the left, all other terms to the right

k=-8

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