5(4+c)=4(c-3)

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Solution for 5(4+c)=4(c-3) equation:


Simplifying
5(4 + c) = 4(c + -3)
(4 * 5 + c * 5) = 4(c + -3)
(20 + 5c) = 4(c + -3)

Reorder the terms:
20 + 5c = 4(-3 + c)
20 + 5c = (-3 * 4 + c * 4)
20 + 5c = (-12 + 4c)

Solving
20 + 5c = -12 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
20 + 5c + -4c = -12 + 4c + -4c

Combine like terms: 5c + -4c = 1c
20 + 1c = -12 + 4c + -4c

Combine like terms: 4c + -4c = 0
20 + 1c = -12 + 0
20 + 1c = -12

Add '-20' to each side of the equation.
20 + -20 + 1c = -12 + -20

Combine like terms: 20 + -20 = 0
0 + 1c = -12 + -20
1c = -12 + -20

Combine like terms: -12 + -20 = -32
1c = -32

Divide each side by '1'.
c = -32

Simplifying
c = -32

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