5(4+2y)=10(2+y)

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Solution for 5(4+2y)=10(2+y) equation:


Simplifying
5(4 + 2y) = 10(2 + y)
(4 * 5 + 2y * 5) = 10(2 + y)
(20 + 10y) = 10(2 + y)
20 + 10y = (2 * 10 + y * 10)
20 + 10y = (20 + 10y)

Add '-20' to each side of the equation.
20 + -20 + 10y = 20 + -20 + 10y

Combine like terms: 20 + -20 = 0
0 + 10y = 20 + -20 + 10y
10y = 20 + -20 + 10y

Combine like terms: 20 + -20 = 0
10y = 0 + 10y
10y = 10y

Add '-10y' to each side of the equation.
10y + -10y = 10y + -10y

Combine like terms: 10y + -10y = 0
0 = 10y + -10y

Combine like terms: 10y + -10y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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