5(4+2x)+(-8x+12)=68

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Solution for 5(4+2x)+(-8x+12)=68 equation:


Simplifying
5(4 + 2x) + (-8x + 12) = 68
(4 * 5 + 2x * 5) + (-8x + 12) = 68
(20 + 10x) + (-8x + 12) = 68

Reorder the terms:
20 + 10x + (12 + -8x) = 68

Remove parenthesis around (12 + -8x)
20 + 10x + 12 + -8x = 68

Reorder the terms:
20 + 12 + 10x + -8x = 68

Combine like terms: 20 + 12 = 32
32 + 10x + -8x = 68

Combine like terms: 10x + -8x = 2x
32 + 2x = 68

Solving
32 + 2x = 68

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-32' to each side of the equation.
32 + -32 + 2x = 68 + -32

Combine like terms: 32 + -32 = 0
0 + 2x = 68 + -32
2x = 68 + -32

Combine like terms: 68 + -32 = 36
2x = 36

Divide each side by '2'.
x = 18

Simplifying
x = 18

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