5(4+2x)+(-8x)+12=68

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Solution for 5(4+2x)+(-8x)+12=68 equation: 



5(4+2x)+(-8x)+12=68

We move all terms to the left:

5(4+2x)+(-8x)+12-(68)=0

We add all the numbers together, and all the variables

5(2x+4)+(-8x)+12-68=0

We add all the numbers together, and all the variables

5(2x+4)+(-8x)-56=0

We multiply parentheses

10x+(-8x)+20-56=0

We get rid of parentheses

10x-8x+20-56=0

We add all the numbers together, and all the variables

2x-36=0

We move all terms containing x to the left, all other terms to the right

2x=36

x=36/2

x=18

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