5(3z-11)=14z-48

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Solution for 5(3z-11)=14z-48 equation:


5(3z-11)=14z-48

We simplify the equation to the form, which is simple to understand 
5(3z-11)=14z-48

Reorder the terms in parentheses
+(+15z-55)=14z-48

Remove unnecessary parentheses
+15z-55=+14z-48

We move all terms containing z to the left and all other terms to the right. 
+15z-14z=-48+55

We simplify left and right side of the equation. 
+1z=+7

We divide both sides of the equation by 1 to get z. 
z=7

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