5(3z-1)-3(z+2)=2(z+1)

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Solution for 5(3z-1)-3(z+2)=2(z+1) equation:


Simplifying
5(3z + -1) + -3(z + 2) = 2(z + 1)

Reorder the terms:
5(-1 + 3z) + -3(z + 2) = 2(z + 1)
(-1 * 5 + 3z * 5) + -3(z + 2) = 2(z + 1)
(-5 + 15z) + -3(z + 2) = 2(z + 1)

Reorder the terms:
-5 + 15z + -3(2 + z) = 2(z + 1)
-5 + 15z + (2 * -3 + z * -3) = 2(z + 1)
-5 + 15z + (-6 + -3z) = 2(z + 1)

Reorder the terms:
-5 + -6 + 15z + -3z = 2(z + 1)

Combine like terms: -5 + -6 = -11
-11 + 15z + -3z = 2(z + 1)

Combine like terms: 15z + -3z = 12z
-11 + 12z = 2(z + 1)

Reorder the terms:
-11 + 12z = 2(1 + z)
-11 + 12z = (1 * 2 + z * 2)
-11 + 12z = (2 + 2z)

Solving
-11 + 12z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-11 + 12z + -2z = 2 + 2z + -2z

Combine like terms: 12z + -2z = 10z
-11 + 10z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-11 + 10z = 2 + 0
-11 + 10z = 2

Add '11' to each side of the equation.
-11 + 11 + 10z = 2 + 11

Combine like terms: -11 + 11 = 0
0 + 10z = 2 + 11
10z = 2 + 11

Combine like terms: 2 + 11 = 13
10z = 13

Divide each side by '10'.
z = 1.3

Simplifying
z = 1.3

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