5(3z-1)-2(z+4)=4(z+1)

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Solution for 5(3z-1)-2(z+4)=4(z+1) equation:


Simplifying
5(3z + -1) + -2(z + 4) = 4(z + 1)

Reorder the terms:
5(-1 + 3z) + -2(z + 4) = 4(z + 1)
(-1 * 5 + 3z * 5) + -2(z + 4) = 4(z + 1)
(-5 + 15z) + -2(z + 4) = 4(z + 1)

Reorder the terms:
-5 + 15z + -2(4 + z) = 4(z + 1)
-5 + 15z + (4 * -2 + z * -2) = 4(z + 1)
-5 + 15z + (-8 + -2z) = 4(z + 1)

Reorder the terms:
-5 + -8 + 15z + -2z = 4(z + 1)

Combine like terms: -5 + -8 = -13
-13 + 15z + -2z = 4(z + 1)

Combine like terms: 15z + -2z = 13z
-13 + 13z = 4(z + 1)

Reorder the terms:
-13 + 13z = 4(1 + z)
-13 + 13z = (1 * 4 + z * 4)
-13 + 13z = (4 + 4z)

Solving
-13 + 13z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-13 + 13z + -4z = 4 + 4z + -4z

Combine like terms: 13z + -4z = 9z
-13 + 9z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-13 + 9z = 4 + 0
-13 + 9z = 4

Add '13' to each side of the equation.
-13 + 13 + 9z = 4 + 13

Combine like terms: -13 + 13 = 0
0 + 9z = 4 + 13
9z = 4 + 13

Combine like terms: 4 + 13 = 17
9z = 17

Divide each side by '9'.
z = 1.888888889

Simplifying
z = 1.888888889

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