5(3z+2)=4-3(z-2)

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Solution for 5(3z+2)=4-3(z-2) equation:


Simplifying
5(3z + 2) = 4 + -3(z + -2)

Reorder the terms:
5(2 + 3z) = 4 + -3(z + -2)
(2 * 5 + 3z * 5) = 4 + -3(z + -2)
(10 + 15z) = 4 + -3(z + -2)

Reorder the terms:
10 + 15z = 4 + -3(-2 + z)
10 + 15z = 4 + (-2 * -3 + z * -3)
10 + 15z = 4 + (6 + -3z)

Combine like terms: 4 + 6 = 10
10 + 15z = 10 + -3z

Add '-10' to each side of the equation.
10 + -10 + 15z = 10 + -10 + -3z

Combine like terms: 10 + -10 = 0
0 + 15z = 10 + -10 + -3z
15z = 10 + -10 + -3z

Combine like terms: 10 + -10 = 0
15z = 0 + -3z
15z = -3z

Solving
15z = -3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '3z' to each side of the equation.
15z + 3z = -3z + 3z

Combine like terms: 15z + 3z = 18z
18z = -3z + 3z

Combine like terms: -3z + 3z = 0
18z = 0

Divide each side by '18'.
z = 0

Simplifying
z = 0

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