5(3y-7)=8y+28

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Solution for 5(3y-7)=8y+28 equation: 



5(3y-7)=8y+28

We move all terms to the left:

5(3y-7)-(8y+28)=0

We multiply parentheses

15y-(8y+28)-35=0

We get rid of parentheses

15y-8y-28-35=0

We add all the numbers together, and all the variables

7y-63=0

We move all terms containing y to the left, all other terms to the right

7y=63

y=63/7

y=9

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