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5(3x-9)-3=5(x-2)+52
We move all terms to the left:
5(3x-9)-3-(5(x-2)+52)=0
We multiply parentheses
15x-(5(x-2)+52)-45-3=0
We calculate terms in parentheses: -(5(x-2)+52), so:We add all the numbers together, and all the variables
5(x-2)+52
We multiply parentheses
5x-10+52
We add all the numbers together, and all the variables
5x+42
Back to the equation:
-(5x+42)
15x-(5x+42)-48=0
We get rid of parentheses
15x-5x-42-48=0
We add all the numbers together, and all the variables
10x-90=0
We move all terms containing x to the left, all other terms to the right
10x=90
x=90/10
x=9
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