5(3x-8)+2(x+1)=64

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Solution for 5(3x-8)+2(x+1)=64 equation: 



5(3x-8)+2(x+1)=64

We move all terms to the left:

5(3x-8)+2(x+1)-(64)=0

We multiply parentheses

15x+2x-40+2-64=0

We add all the numbers together, and all the variables

17x-102=0

We move all terms containing x to the left, all other terms to the right

17x=102

x=102/17

x=6

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