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5(3x-7)=9x+1
We move all terms to the left:
5(3x-7)-(9x+1)=0
We multiply parentheses
15x-(9x+1)-35=0
We get rid of parentheses
15x-9x-1-35=0
We add all the numbers together, and all the variables
6x-36=0
We move all terms containing x to the left, all other terms to the right
6x=36
x=36/6
x=6
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