5(3x-7)-3(6x+8)=6(12-x)+1

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Solution for 5(3x-7)-3(6x+8)=6(12-x)+1 equation: 



5(3x-7)-3(6x+8)=6(12-x)+1

We move all terms to the left:

5(3x-7)-3(6x+8)-(6(12-x)+1)=0

We add all the numbers together, and all the variables

5(3x-7)-3(6x+8)-(6(-1x+12)+1)=0

We multiply parentheses

15x-18x-(6(-1x+12)+1)-35-24=0



We calculate terms in parentheses: -(6(-1x+12)+1), so:

6(-1x+12)+1

We multiply parentheses

-6x+72+1

We add all the numbers together, and all the variables

-6x+73

Back to the equation:

-(-6x+73)



We add all the numbers together, and all the variables

-3x-(-6x+73)-59=0

We get rid of parentheses

-3x+6x-73-59=0

We add all the numbers together, and all the variables

3x-132=0

We move all terms containing x to the left, all other terms to the right

3x=132

x=132/3

x=44

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