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5(3x-5)-3=5(x-2)+2
We move all terms to the left:
5(3x-5)-3-(5(x-2)+2)=0
We multiply parentheses
15x-(5(x-2)+2)-25-3=0
We calculate terms in parentheses: -(5(x-2)+2), so:We add all the numbers together, and all the variables
5(x-2)+2
We multiply parentheses
5x-10+2
We add all the numbers together, and all the variables
5x-8
Back to the equation:
-(5x-8)
15x-(5x-8)-28=0
We get rid of parentheses
15x-5x+8-28=0
We add all the numbers together, and all the variables
10x-20=0
We move all terms containing x to the left, all other terms to the right
10x=20
x=20/10
x=2
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