5(3x-2)=9(x-4)-7x

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Solution for 5(3x-2)=9(x-4)-7x equation: 



5(3x-2)=9(x-4)-7x

We move all terms to the left:

5(3x-2)-(9(x-4)-7x)=0

We multiply parentheses

15x-(9(x-4)-7x)-10=0



We calculate terms in parentheses: -(9(x-4)-7x), so:

9(x-4)-7x

We add all the numbers together, and all the variables

-7x+9(x-4)

We multiply parentheses

-7x+9x-36

We add all the numbers together, and all the variables

2x-36

Back to the equation:

-(2x-36)



We get rid of parentheses

15x-2x+36-10=0

We add all the numbers together, and all the variables

13x+26=0

We move all terms containing x to the left, all other terms to the right

13x=-26

x=-26/13

x=-2

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