5(3x-2)=10(x-3)+10x

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Solution for 5(3x-2)=10(x-3)+10x equation: 



5(3x-2)=10(x-3)+10x

We move all terms to the left:

5(3x-2)-(10(x-3)+10x)=0

We multiply parentheses

15x-(10(x-3)+10x)-10=0



We calculate terms in parentheses: -(10(x-3)+10x), so:

10(x-3)+10x

We add all the numbers together, and all the variables

10x+10(x-3)

We multiply parentheses

10x+10x-30

We add all the numbers together, and all the variables

20x-30

Back to the equation:

-(20x-30)



We get rid of parentheses

15x-20x+30-10=0

We add all the numbers together, and all the variables

-5x+20=0

We move all terms containing x to the left, all other terms to the right

-5x=-20

x=-20/-5

x=+4

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