5(3x-2)=10(x+3)

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Solution for 5(3x-2)=10(x+3) equation: 



5(3x-2)=10(x+3)

We move all terms to the left:

5(3x-2)-(10(x+3))=0

We multiply parentheses

15x-(10(x+3))-10=0



We calculate terms in parentheses: -(10(x+3)), so:

10(x+3)

We multiply parentheses

10x+30

Back to the equation:

-(10x+30)



We get rid of parentheses

15x-10x-30-10=0

We add all the numbers together, and all the variables

5x-40=0

We move all terms containing x to the left, all other terms to the right

5x=40

x=40/5

x=8

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