5(3x-2)=(3x+11)+8

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Solution for 5(3x-2)=(3x+11)+8 equation: 



5(3x-2)=(3x+11)+8

We move all terms to the left:

5(3x-2)-((3x+11)+8)=0

We multiply parentheses

15x-((3x+11)+8)-10=0



We calculate terms in parentheses: -((3x+11)+8), so:

(3x+11)+8

We get rid of parentheses

3x+11+8

We add all the numbers together, and all the variables

3x+19

Back to the equation:

-(3x+19)



We get rid of parentheses

15x-3x-19-10=0

We add all the numbers together, and all the variables

12x-29=0

We move all terms containing x to the left, all other terms to the right

12x=29

x=29/12

x=2+5/12

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