5(3x-2)-5=5(x-5)+60

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Solution for 5(3x-2)-5=5(x-5)+60 equation: 



5(3x-2)-5=5(x-5)+60

We move all terms to the left:

5(3x-2)-5-(5(x-5)+60)=0

We multiply parentheses

15x-(5(x-5)+60)-10-5=0



We calculate terms in parentheses: -(5(x-5)+60), so:

5(x-5)+60

We multiply parentheses

5x-25+60

We add all the numbers together, and all the variables

5x+35

Back to the equation:

-(5x+35)



We add all the numbers together, and all the variables

15x-(5x+35)-15=0

We get rid of parentheses

15x-5x-35-15=0

We add all the numbers together, and all the variables

10x-50=0

We move all terms containing x to the left, all other terms to the right

10x=50

x=50/10

x=5

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