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5(3x-2)-2(2x-17)=5(2x+1)-1
We move all terms to the left:
5(3x-2)-2(2x-17)-(5(2x+1)-1)=0
We multiply parentheses
15x-4x-(5(2x+1)-1)-10+34=0
We calculate terms in parentheses: -(5(2x+1)-1), so:We add all the numbers together, and all the variables
5(2x+1)-1
We multiply parentheses
10x+5-1
We add all the numbers together, and all the variables
10x+4
Back to the equation:
-(10x+4)
11x-(10x+4)+24=0
We get rid of parentheses
11x-10x-4+24=0
We add all the numbers together, and all the variables
x+20=0
We move all terms containing x to the left, all other terms to the right
x=-20
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