5(3x-2)+4(6-x)=4x+47

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Solution for 5(3x-2)+4(6-x)=4x+47 equation: 



5(3x-2)+4(6-x)=4x+47

We move all terms to the left:

5(3x-2)+4(6-x)-(4x+47)=0

We add all the numbers together, and all the variables

5(3x-2)+4(-1x+6)-(4x+47)=0

We multiply parentheses

15x-4x-(4x+47)-10+24=0

We get rid of parentheses

15x-4x-4x-47-10+24=0

We add all the numbers together, and all the variables

7x-33=0

We move all terms containing x to the left, all other terms to the right

7x=33

x=33/7

x=4+5/7

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