5(3x-2)+(4x-5)=(3x-5)-(2x+3)

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Solution for 5(3x-2)+(4x-5)=(3x-5)-(2x+3) equation: 



5(3x-2)+(4x-5)=(3x-5)-(2x+3)

We move all terms to the left:

5(3x-2)+(4x-5)-((3x-5)-(2x+3))=0

We multiply parentheses

15x+(4x-5)-((3x-5)-(2x+3))-10=0

We get rid of parentheses

15x+4x-((3x-5)-(2x+3))-5-10=0



We calculate terms in parentheses: -((3x-5)-(2x+3)), so:

(3x-5)-(2x+3)

We get rid of parentheses

3x-2x-5-3

We add all the numbers together, and all the variables

x-8

Back to the equation:

-(x-8)



We add all the numbers together, and all the variables

19x-(x-8)-15=0

We get rid of parentheses

19x-x+8-15=0

We add all the numbers together, and all the variables

18x-7=0

We move all terms containing x to the left, all other terms to the right

18x=7

x=7/18

x=7/18

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