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5(3x-1)-3(2x-19)=2(4x+1)-1
We move all terms to the left:
5(3x-1)-3(2x-19)-(2(4x+1)-1)=0
We multiply parentheses
15x-6x-(2(4x+1)-1)-5+57=0
We calculate terms in parentheses: -(2(4x+1)-1), so:We add all the numbers together, and all the variables
2(4x+1)-1
We multiply parentheses
8x+2-1
We add all the numbers together, and all the variables
8x+1
Back to the equation:
-(8x+1)
9x-(8x+1)+52=0
We get rid of parentheses
9x-8x-1+52=0
We add all the numbers together, and all the variables
x+51=0
We move all terms containing x to the left, all other terms to the right
x=-51
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