5(3x+55)=4(x+33)

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Solution for 5(3x+55)=4(x+33) equation: 



5(3x+55)=4(x+33)

We move all terms to the left:

5(3x+55)-(4(x+33))=0

We multiply parentheses

15x-(4(x+33))+275=0



We calculate terms in parentheses: -(4(x+33)), so:

4(x+33)

We multiply parentheses

4x+132

Back to the equation:

-(4x+132)



We get rid of parentheses

15x-4x-132+275=0

We add all the numbers together, and all the variables

11x+143=0

We move all terms containing x to the left, all other terms to the right

11x=-143

x=-143/11

x=-13

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