5(3x+4)=7(x-6)+19

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Solution for 5(3x+4)=7(x-6)+19 equation: 



5(3x+4)=7(x-6)+19

We move all terms to the left:

5(3x+4)-(7(x-6)+19)=0

We multiply parentheses

15x-(7(x-6)+19)+20=0



We calculate terms in parentheses: -(7(x-6)+19), so:

7(x-6)+19

We multiply parentheses

7x-42+19

We add all the numbers together, and all the variables

7x-23

Back to the equation:

-(7x-23)



We get rid of parentheses

15x-7x+23+20=0

We add all the numbers together, and all the variables

8x+43=0

We move all terms containing x to the left, all other terms to the right

8x=-43

x=-43/8

x=-5+3/8

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