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5(3x+4)=2(4x-11)
We move all terms to the left:
5(3x+4)-(2(4x-11))=0
We multiply parentheses
15x-(2(4x-11))+20=0
We calculate terms in parentheses: -(2(4x-11)), so:We get rid of parentheses
2(4x-11)
We multiply parentheses
8x-22
Back to the equation:
-(8x-22)
15x-8x+22+20=0
We add all the numbers together, and all the variables
7x+42=0
We move all terms containing x to the left, all other terms to the right
7x=-42
x=-42/7
x=-6
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