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5(3x+2)=3(3x+3)
We move all terms to the left:
5(3x+2)-(3(3x+3))=0
We multiply parentheses
15x-(3(3x+3))+10=0
We calculate terms in parentheses: -(3(3x+3)), so:We get rid of parentheses
3(3x+3)
We multiply parentheses
9x+9
Back to the equation:
-(9x+9)
15x-9x-9+10=0
We add all the numbers together, and all the variables
6x+1=0
We move all terms containing x to the left, all other terms to the right
6x=-1
x=-1/6
x=-1/6
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