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5(3x+2)-2x(2+x)=(2+x)(5-2x)
We move all terms to the left:
5(3x+2)-2x(2+x)-((2+x)(5-2x))=0
We add all the numbers together, and all the variables
5(3x+2)-2x(x+2)-((x+2)(-2x+5))=0
We multiply parentheses
-2x^2+15x-4x-((x+2)(-2x+5))+10=0
We multiply parentheses ..
-2x^2-((-2x^2+5x-4x+10))+15x-4x+10=0
We calculate terms in parentheses: -((-2x^2+5x-4x+10)), so:We add all the numbers together, and all the variables
(-2x^2+5x-4x+10)
We get rid of parentheses
-2x^2+5x-4x+10
We add all the numbers together, and all the variables
-2x^2+x+10
Back to the equation:
-(-2x^2+x+10)
-2x^2-(-2x^2+x+10)+11x+10=0
We get rid of parentheses
-2x^2+2x^2-x+11x-10+10=0
We add all the numbers together, and all the variables
10x=0
x=0/10
x=0
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