5(3x+2)+15=7(9x+3)+8x

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Solution for 5(3x+2)+15=7(9x+3)+8x equation: 



5(3x+2)+15=7(9x+3)+8x

We move all terms to the left:

5(3x+2)+15-(7(9x+3)+8x)=0

We multiply parentheses

15x-(7(9x+3)+8x)+10+15=0



We calculate terms in parentheses: -(7(9x+3)+8x), so:

7(9x+3)+8x

We add all the numbers together, and all the variables

8x+7(9x+3)

We multiply parentheses

8x+63x+21

We add all the numbers together, and all the variables

71x+21

Back to the equation:

-(71x+21)



We add all the numbers together, and all the variables

15x-(71x+21)+25=0

We get rid of parentheses

15x-71x-21+25=0

We add all the numbers together, and all the variables

-56x+4=0

We move all terms containing x to the left, all other terms to the right

-56x=-4

x=-4/-56

x=1/14

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