5(3x+1)=6(x+5)+5

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Solution for 5(3x+1)=6(x+5)+5 equation: 



5(3x+1)=6(x+5)+5

We move all terms to the left:

5(3x+1)-(6(x+5)+5)=0

We multiply parentheses

15x-(6(x+5)+5)+5=0



We calculate terms in parentheses: -(6(x+5)+5), so:

6(x+5)+5

We multiply parentheses

6x+30+5

We add all the numbers together, and all the variables

6x+35

Back to the equation:

-(6x+35)



We get rid of parentheses

15x-6x-35+5=0

We add all the numbers together, and all the variables

9x-30=0

We move all terms containing x to the left, all other terms to the right

9x=30

x=30/9

x=3+1/3

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