5(3x+-2)=2(6x+3)

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Solution for 5(3x+-2)=2(6x+3) equation:



5(3x+-2)=2(6x+3)
We move all terms to the left:
5(3x+-2)-(2(6x+3))=0
We add all the numbers together, and all the variables
5(3x-2)-(2(6x+3))=0
We multiply parentheses
15x-(2(6x+3))-10=0
We calculate terms in parentheses: -(2(6x+3)), so:
2(6x+3)
We multiply parentheses
12x+6
Back to the equation:
-(12x+6)
We get rid of parentheses
15x-12x-6-10=0
We add all the numbers together, and all the variables
3x-16=0
We move all terms containing x to the left, all other terms to the right
3x=16
x=16/3
x=5+1/3

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