5(3v-5)(v+4)=0

Solution for 5(3v-5)(v+4)=0 equation:

5(3v-5)(v+4)=0

We multiply parentheses ..

5(+3v^2+12v-5v-20)=0

We multiply parentheses

15v^2+60v-25v-100=0

We add all the numbers together, and all the variables

15v^2+35v-100=0

a = 15; b = 35; c = -100;
Δ = b2-4ac
Δ = 352-4·15·(-100)
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7225}=85$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-85}{2*15}=\frac{-120}{30}
=-4
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+85}{2*15}=\frac{50}{30}
=1+2/3
$