5(3r-1)=-7(2+r)

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Solution for 5(3r-1)=-7(2+r) equation: 



5(3r-1)=-7(2+r)

We move all terms to the left:

5(3r-1)-(-7(2+r))=0

We add all the numbers together, and all the variables

5(3r-1)-(-7(r+2))=0

We multiply parentheses

15r-(-7(r+2))-5=0



We calculate terms in parentheses: -(-7(r+2)), so:

-7(r+2)

We multiply parentheses

-7r-14

Back to the equation:

-(-7r-14)



We get rid of parentheses

15r+7r+14-5=0

We add all the numbers together, and all the variables

22r+9=0

We move all terms containing r to the left, all other terms to the right

22r=-9

r=-9/22

r=-9/22

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