5(3r+4)=9+(6r-7)

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Solution for 5(3r+4)=9+(6r-7) equation: 



5(3r+4)=9+(6r-7)

We move all terms to the left:

5(3r+4)-(9+(6r-7))=0

We multiply parentheses

15r-(9+(6r-7))+20=0



We calculate terms in parentheses: -(9+(6r-7)), so:

9+(6r-7)

determiningTheFunctionDomain
(6r-7)+9

We get rid of parentheses

6r-7+9

We add all the numbers together, and all the variables

6r+2

Back to the equation:

-(6r+2)



We get rid of parentheses

15r-6r-2+20=0

We add all the numbers together, and all the variables

9r+18=0

We move all terms containing r to the left, all other terms to the right

9r=-18

r=-18/9

r=-2

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