5(3j+2)=4j+32

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Solution for 5(3j+2)=4j+32 equation: 



5(3j+2)=4j+32

We move all terms to the left:

5(3j+2)-(4j+32)=0

We multiply parentheses

15j-(4j+32)+10=0

We get rid of parentheses

15j-4j-32+10=0

We add all the numbers together, and all the variables

11j-22=0

We move all terms containing j to the left, all other terms to the right

11j=22

j=22/11

j=2

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