5(3c-2)-7c=40-3c

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Solution for 5(3c-2)-7c=40-3c equation:



5(3c-2)-7c=40-3c
We move all terms to the left:
5(3c-2)-7c-(40-3c)=0
We add all the numbers together, and all the variables
5(3c-2)-7c-(-3c+40)=0
We add all the numbers together, and all the variables
-7c+5(3c-2)-(-3c+40)=0
We multiply parentheses
-7c+15c-(-3c+40)-10=0
We get rid of parentheses
-7c+15c+3c-40-10=0
We add all the numbers together, and all the variables
11c-50=0
We move all terms containing c to the left, all other terms to the right
11c=50
c=50/11
c=4+6/11

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