5(3c-2)+1=-(c-7)

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Solution for 5(3c-2)+1=-(c-7) equation: 



5(3c-2)+1=-(c-7)

We move all terms to the left:

5(3c-2)+1-(-(c-7))=0

We multiply parentheses

15c-(-(c-7))-10+1=0



We calculate terms in parentheses: -(-(c-7)), so:

-(c-7)

We get rid of parentheses

-c+7

We add all the numbers together, and all the variables

-1c+7

Back to the equation:

-(-1c+7)



We add all the numbers together, and all the variables

15c-(-1c+7)-9=0

We get rid of parentheses

15c+1c-7-9=0

We add all the numbers together, and all the variables

16c-16=0

We move all terms containing c to the left, all other terms to the right

16c=16

c=16/16

c=1

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