5(3c-1-2)=13c+9

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Solution for 5(3c-1-2)=13c+9 equation: 



5(3c-1-2)=13c+9

We move all terms to the left:

5(3c-1-2)-(13c+9)=0

We add all the numbers together, and all the variables

5(3c-3)-(13c+9)=0

We multiply parentheses

15c-(13c+9)-15=0

We get rid of parentheses

15c-13c-9-15=0

We add all the numbers together, and all the variables

2c-24=0

We move all terms containing c to the left, all other terms to the right

2c=24

c=24/2

c=12

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