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x in (-oo:+oo)
5*((3/5)*x+2) = 3*x+10 // - 3*x+10
5*((3/5)*x+2)-(3*x)-10 = 0
5*((3/5)*x+2)-3*x-10 = 0
5*(3/5*x+2)-3*x-10 = 0
5*(3/5*x+2)-3*x-10 = 0
10-10 = 0
0 = 0
0 = 0
x belongs to the empty set
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