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5(3/2x)=10x-4
We move all terms to the left:
5(3/2x)-(10x-4)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5(+3/2x)-(10x-4)=0
We multiply parentheses
15x-(10x-4)=0
We get rid of parentheses
15x-10x+4=0
We add all the numbers together, and all the variables
5x+4=0
We move all terms containing x to the left, all other terms to the right
5x=-4
x=-4/5
x=-4/5
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